MathOverflow

Math Overflow. Q&A for professional mathematicians.

Read Mathoverflow.net news digest here: view the latest Math Overflow articles and content updates right away or get to their most visited pages. Mathoverflow.net belongs to a group of fairly successful websites, with more than 458K visitors from all over the world monthly. It seems that Math Overflow content is notably popular in USA, as 32.4% of all users (148K visits per month) come from this country. We haven’t detected security issues or inappropriate content on Mathoverflow.net and thus you can safely use it. Mathoverflow.net is hosted with Stack Exchange, Inc. (United States) and its basic language is English.

  • Content verdict: Safe
  • Website availability: Live
  • English language flagLanguage: English
  • Last check:
  • 15 260

    Visitors daily
  • 54 936

    Pageviews daily
  • 6

    Google PR
  • 20 836

    Alexa rank

Mathoverflow.net news digest

  • 8 years

    Boundary of the image of a projection

    Let $U$ be a connected open subset in $\mathbb{R^n}$. Let $f: U \rightarrow U$ be a differentiable projection, i.e. $f\circ f = f$. It's well-known that $f(U)$ is a submanifold of $U$ (Henri Cartan, Sur les rétractions d’une variété.(1986). My question...

  • 4 years

    VC dimension of a certain derived class of binary functions

    Let $X$ be a measurable space and let $P$ be a probability distribution on $X \times \{\pm 1\}$. Let $F$ be a function class on $X$, i.e., a collection of (measurable) functions from $X$ to $\mathbb R$. Fix $\alpha \in \mathbb R$ and $\beta > 0$...

  • 11 years

    Does one real radical root imply they all are?

    Is there an example of an irreducible polynomial $f(x) \in \mathbb{Q}[x]$ with a real root expressible in terms of real radicals and another real root not expressible in terms of real radicals?

  • 0 days

    Axiomatizing a "bounded" companion of PA

    This was originally asked at MSE without success.
    Let $$PA_{bd}=\{\varphi: PA\vdash\forall^\infty n([n]\models\varphi)\},$$ where $[n]=\{0,1,...,n\}$ (with $+$ and $\times$ interpreted as $$a+^{[n]}b=\min\{a+b, n\},\quad a\times^{[n]}b=\min\{a\times b, n\}$$ so that this actually makes sense - we could...

Domain history

Web host: Stack Exchange, Inc.
Registrar: GoDaddy.com, LLC
Registrant: Registration Private (Domains By Proxy, LLC)
Updated: July 07, 2025
Expires: July 14, 2026
Created: July 14, 2009

Whois record

Visitor gender

Male

Female

Safety scores

Trustworthiness

Excellent

Child safety

Excellent